args to hours, mins & seconds

You can use String#indexOf

Code (Text):

String args = "1h3s5m"
int h = args[args.indexOf("h")-1]

 

Then you do the same thing for the others

 

true(plus the code i gave you was wrong).

My suggestion would be to still get the index of the letter, but then have a loop that goes thrrough and checks how far the number goes back.

Code (Text):

String args = "1h3s5m"

int last = args.indexOf("h")
int first;
for(int i = last; i >= 0; i--){
  if(isANumber(args[i]))
    first = i;
  else
    break;
}
int h = args.substring(first, last);
 

But you'd have to make the code to check if it's a number

 

The code I gave before would return the index not the value, you'd have to args[h], args[m], etc. Although as you said it would only work for single digits.

the fact that you're allowing them to switch the hours,minutes, and seconds is what makes it a little tricky.

 

Yes, that'll be much easier. You can just then split it at ":" and youll get hrs, mins and sec respectively.

 

Using the colons would probably make it the easiest.

 

You could also use the h m s and but in the format 1h.2s so you split it at the "." and iterate through the string you get when split. Then you check to see which letter it ends in and do what u wanna do.

 

You can try to use this method :

Code (Text):

    public Date parseDate(String date){
        int weeks = 0;
        int days = 0;
        int hours = 0;
        int mins = 0;
        int secs = 0;
       
        String nums = "";
        for(int j = 0; j < date.length(); j++){
            String c = date.substring(j, j + 1);
            try {
                Integer.parseInt(c);
                nums = new StringBuilder().append(nums).append(c).toString();
            } catch (Exception e) {
                int num = Integer.parseInt(nums);
                if(c.equals("w"))weeks = num;
                else if(c.equals("d"))days = num;
                else if(c.equals("h"))hours = num;
                else if(c.equals("m"))mins = num;
                else if(c.equals("s"))secs = num;
                else throw new IllegalArgumentException("Invalid time measurement: " + c);
                nums = "";
            }
        }
       
        long time = 0;
       
        time += TimeUnit.SECONDS.toMillis(secs);
        time += TimeUnit.MINUTES.toMillis(mins);
        time += TimeUnit.HOURS.toMillis(hours);
        time += TimeUnit.DAYS.toMillis(days);
        time += TimeUnit.DAYS.toMillis(weeks*7);
       
        return new Date(time);
    }

Command you type :

Code (Text):

/timetest 5h2s3m

Get the argument :

Code (Text):

String time = args[0];

Parse it

Code (Text):

Date time = parseDate(time);

and finally, you can use the following methods to parse the time with the Date object which was returned with the parse method.

Code (Text):

long timeMillis = date.getTime();

int days = Math.ceil((int) TimeUnit.MILLISECONDS.toDays(timeMillis));
int weeks = Math.ceil(days / 7);
timeMillis -= TimeUnit.DAYS.toMillis(days);
int hours = Math.ceil((int) TimeUnit.MILLISECONDS.toHours(timeMillis));
timeMillis -= TimeUnit.HOURS.toMillis(hours);
int minutes = Math.ceil((int) TimeUnit.MILLISECONDS.toMinutes(timeMillis));
timeMillis -= TimeUnit.MINUTES.toMillis(minutes);
int seconds = Math.ceil((int) TimeUnit.MILLISECONDS.toSeconds(timeMillis));

Edit: Not tested yet, if it don't work, tell me!

 

Well, it's just a utility method, so you don't REALLY have to understand it as long as you know the output. You can go over it later and take time to learn the algorithms (I don't always learn the algorithms myself but just find them on the internet, and sometimes I go back later).