Replace text in a sign

You'll have to use Sign#setLine and once you're done doing them, do #update

 

Get the original text, change it then set it back to the sign.

 

But that's not how Java works. You're replacing the text represented in the String Object, but you still have to connect it to the actual sign with the set method. Also, I think you should add s.update() at the end of the method sothat the changes get visible.

 

Normally I don't write the code myself, but I couldn't think of a way to explain this clearly. Understand what it does before you use it.

EDIT, didn't work. Now it does.

Code (Text):

    @EventHandler
    public void placeSign(SignChangeEvent sign) {
        Player p = sign.getPlayer();
        Sign s = (Sign) sign.getBlock().getState();

        String[] lines = s.getLines();

        for (int i = 0; i < lines.length; i++) {
            if (p.hasPermission("coloredsigns.position")) {
                String line = lines[i];
                line = line.replaceAll("<x>", (int) sign.getBlock().getLocation().getX() + "");
                line = line.replaceAll("<y>", (int) sign.getBlock().getLocation().getY() + "");
                line = line.replaceAll("<z>", (int) sign.getBlock().getLocation().getZ() + "");
                s.setLine(i, line);
            }
        }
        s.update();
    }
 

 

set the message with . the sign message .replace("%something%", Replacement); then update.

 

what a cute spoon isn't it ?

 

Like I said, I couldn't think of a way to explain this clearly. Apparently you didn't either, because he most likely didn't understand anything of it after reading what you said, neither did I.

 

you didn't because like what you've said you even don't understand what is the shit with the code you've been copied with.

 

Maybe it's because English isn't my native language, but I've no idea what you're trying to say

 

I have no idea either I think its been far with the problem itself to keep this nonsense discussion.

 

In this example I think it's fine to "spoonfeed". I wouldn't neccessarily call it that in this instance.

 

Yayy!!! a hero please stop that man to do this mistakes again mr . Rubix .

 

That's why you could have said nothing as others already gave the solution.

 

Try debugging where your code gets using a few debug statements. It was untested